For the large conical water tank at your warehouse, the volume $V$ of water in the tank measured in cubic feet is related to the height $h$ of water in the tank in feet by the formula $V = \frac{1}{9}\pi h^3$. The tank is being filled with water at a constant rate of 1.6 cubic feet per second. Find the rate at which the height is increasing when the height is 8 feet. (Round your answer to two decimal places.) Rate:
Added by Lidia R.
Close
Step 1
We are also given that the tank is being filled with water at a constant rate of 1.6 cubic feet per second. This means that $\frac{dV}{dt} = 1.6$. We want to find the rate at which the height is increasing when the height is 8 feet, which is $\frac{dh}{dt}$ when Show more…
Show all steps
Your feedback will help us improve your experience
Adi S and 89 other Calculus 1 / AB educators are ready to help you.
Ask a new question
Labs
Want to see this concept in action?
Explore this concept interactively to see how it behaves as you change inputs.
Key Concepts
Recommended Videos
A conical tank (with circular base on top) is being filled with water at a constant rate. The tank has base radius 6 feet and height 8 feet. If the water level is rising at 1 inch per second when the water is 4 feet deep, at what rate is the tank being filled (in cubic feet per second)?
Adi S.
Water is poured into a conical tank at a constant rate of 6 cubic feet per minute. The tank is 12 feet deep and has a radius of 4 feet at the top as shown. The shaded region is the water. Its volume is V = 1/27 (π(h^3)). At the instant when h = 8.0 feet, how quickly is the height of the water increasing? Round your answer to two decimal places.
Sri K.
Manisha S.
Recommended Textbooks
Calculus: Early Transcendentals
Thomas Calculus
Transcript
Watch the video solution with this free unlock.
EMAIL
PASSWORD