Question

Part 3 of 5 For the last term $xy^3$, note that it is also a product, and so we must again use the Product Rule. We therefore have the following. $\frac{d}{dx}[xy^3] = (x)(\text{_}) \cdot y' + (y^3)(\text{_})$

          Part 3 of 5
For the last term $xy^3$, note that it is also a product, and so we must again use the Product Rule. We therefore
have the following.
$\frac{d}{dx}[xy^3] = (x)(\text{_____}) \cdot y' + (y^3)(\text{_____})$

Part 3 of 5
For the last term xy^3, note that it is also a product, and so we must again use the Product Rule. We therefore
have the following.
(d)/(dx)[xy^3] = (x)() · y' + (y^3)()

Added by Amanda H.

Calculus: Early Transcendentals

James Stewart 8th Edition

Instant Answer

Solved by Expert Sri K

10/02/2023

Step 1

Mathematically, this can be written as: (d/dx)[f(x)g(x)] = f'(x)g(x) + f(x)g'(x) Show more…

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For the last term xy^(3), note that it is also a product, and so we must again use the Product Rule. We therefore have the following. (d)/(dx)[xy^(3)]=(x)(,y^('))+(y^(3))(◻) Part3of5 For the last term xy3, note that it is also a product, and so we must again use the Product Rule. We therefore have the following.