00:01
Hi, in the given problem we are given with a matrix a and that is 2, minus 2, 3, 0, 3, minus 2, 0, minus 1, 2.
00:17
So, let's find the eigenvalue a minus lambda i, determinant of that is 0.
00:23
So, this means we have the determinant 2 minus lambda 0, 0, minus 2, 3 minus lambda, minus 1, 3, minus 2, 2 minus lambda, the determinant of that is 0.
00:43
So, from here we get 2 lambda plus 2 minus lambda whole square times 3 minus lambda minus 4 is equal to 0.
01:05
So, this means we get lambda is lambda 1 is equal to 1, lambda 2 is equal to 2, lambda 3 is equal to 4.
01:15
So, these are the eigenvalues.
01:21
Now, for lambda is equal to 1, the eigenvector is for lambda 1 is equal to 1, eigenvector would be v1 is equal to minus 1, 1, t...