00:01
Hi, in this question we are given with this reaction in which 2a plus b reacts to give product.
00:06
The rate law expression for this reaction is k into concentration of a raise to power 2.
00:13
It means it is the second order reaction.
00:22
This power is representing the order of reaction.
00:25
The rate constant value is given as 0 .035 per molar per minute.
00:30
This unit is also representing the second order reaction.
00:34
The initial concentration of a is given as 0 .50 molar and concentration at time t is 0 .25 molar.
00:43
We are asked to find out this time value in which the concentration become 2 .5 molar.
00:49
Here, according to second order reaction, we are having the expression that is k, that is rate constant, is equal to 1 over t, into 1 over concentration of a at time t minus 1 over concentration of a at 0 time time or we can say initial time...