For the reaction 2Fe(s) + 3Cl2(g) → 2FeCl3(s) ΔG° = -673.1 kJ and ΔS° = -440.3 J/K at 286 K and 1 atm. The maximum amount of work that could be done by this reaction when 1.70 moles of Fe(s) react at standard conditions at this temperature is ____ kJ.
Added by Joseph H.
Step 1
First, we need to find the Gibbs free energy change (ΔG) for 1.70 moles of Fe(s) reacting. Since the given ΔG° is for 2 moles of Fe(s), we can calculate ΔG for 1.70 moles as follows: ΔG = (1.70 mol Fe / 2 mol Fe) × (-673.1 kJ) Show more…
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