00:01
Hello students, we will discuss a problem of chemical kinetics and the reaction is a plus 2b is equal to 2c plus 2d.
00:14
It is a homogeneous reaction where every component is present into the gaseous state.
00:20
We are supposed to crack the rate law for this reaction.
00:26
In other words, we need to know order of reaction.
00:31
And, four trials has been done with respect to this particular experiment.
00:43
Let's take the trial 1 and trial 2.
00:55
When we combined it, we can write the rate law and rate law is equal to rate is equal to rate constant multiplied by a concentration of a to the rate to the rate law the power a, concentration of b to the power b.
01:18
For trial 1, the rate is 7 .25.
01:24
For trial 2, the rate is 21 .75 and this is equal to rate constant that will remain constant for both.
01:36
And for the first trial, the concentration of a has been taken as 0 .1 to 5 to the power a for the second .375 to the power a and concentration of p is .2000 to the power b and concentration of p is .200 to the power b and for second tier also .200 to the power b.
02:06
This will get cancelled, this would cancel and this will be equal to 1 divided by 3 and this is equal to 1 divided by 3 to the power a.
02:19
So, it is naturally coming as a is equal to 1...