For the reaction AgI(s) + (1/2)Br2(g) ? AgBr(s) + (1/2)I2(s) ?H°(298) = -54.0 kJ ?H°f for AgBr(s) = -100.4 kJ/mol ?H°f for Br2(g) = +30.9 kJ/mol The value of delta ?H°f(298) for AgI(s) is +77.3 kJ/mol -77.3 kJ/mol -123.5 kJ/mol -61.8 kJ/mol +61.8 kJ/mol
Added by Paul Z.
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