Question

For the reaction below, the enthalpy of reaction is ??H = -22.97 kJ mol?¹ and the thermodynamic equilibrium constant is K = 2.34×10?? at 298.15 K. What is the value of K at 256 K? C(gr.) + ½ N?(g) + ?/? H?(g) ? CH?NH?(g) Enter your answer with 3 significant figures. Enter 1.25×10?? as 1.25e-4 and 7.38×10² as 7.38e2. K = Number at 256 K

          For the reaction below, the enthalpy of reaction is ??H = -22.97 kJ mol?¹ and the thermodynamic equilibrium constant is K = 2.34×10?? at 298.15 K. What is the value of K at 256 K?

C(gr.) + ½ N?(g) + ?/? H?(g) ? CH?NH?(g)

Enter your answer with 3 significant figures.
Enter 1.25×10?? as 1.25e-4 and 7.38×10² as 7.38e2.

K = Number at 256 K

For the reaction below, the enthalpy of reaction is ??H = -22.97 kJ mol?¹ and the thermodynamic equilibrium constant is K = 2.34×10?? at 298.15 K. What is the value of K at 256 K?

C(gr.) + ½ N?(g) + ?/? H?(g) ? CH?NH?(g)

Enter your answer with 3 significant figures.
Enter 1.25×10?? as 1.25e-4 and 7.38×10² as 7.38e2.

K = Number at 256 K

Added by Jennifer A.

Chemistry: Structure and Properties

Nivaldo Tro 2nd Edition

Instant Answer

Solved by Expert Supreeta N

03/14/2023

Step 1

97 kJ mol-1 and the thermodynamic equilibrium constant is K= 2.34*10-6 at 298.15 K Show more…

Show all steps

Thanks for your feedback!

For the reaction below, the enthalpy of reaction is ΔrH = -22.97 kJ mol⁻¹ and the thermodynamic equilibrium constant is K = 2.34 × 10⁻⁶ at 298.15 K. What is the value of K at 256 K? C(gr.) + 1/2 N₂(g) + 5/2 H₂(g) ⟶ CH₃NH₂(g) Enter your answer with 3 significant figures. Enter 1.25×10⁻⁴ as 1.25e-4 and 7.38×10² as 7.38e2. K = [Number] at 256 K