Question

For the reaction of hydrazine (N2H4) in water, H2NNH2(aq) + H2O(l) ? H2NNH3+(aq) + OH-(aq) Kb is 3.0 × 10^-6. Calculate the concentrations of all species and the pH of a 2.9-M solution of hydrazine in water. [H2NNH2] = M [H2NNH3+] = M [OH-] = M [H+] = M pH =

          For the reaction of hydrazine (N2H4) in water,
H2NNH2(aq) + H2O(l) ? H2NNH3+(aq) + OH-(aq)
Kb is 3.0 × 10^-6. Calculate the concentrations of all species and the pH of a 2.9-M solution of hydrazine in water.
[H2NNH2] = M
[H2NNH3+] = M
[OH-] = M
[H+] = M
pH =

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For the reaction of hydrazine (N2H4) in water,
H2NNH2(aq) + H2O(l) ? H2NNH3+(aq) + OH-(aq)
Kb is 3.0 × 10^-6. Calculate the concentrations of all species and the pH of a 2.9-M solution of hydrazine in water.
[H2NNH2] = M
[H2NNH3+] = M
[OH-] = M
[H+] = M
pH =

Added by Hayley T.

Chemistry: Structure and Properties

Nivaldo Tro 2nd Edition

Instant Answer

Solved by Expert Susan Hallstrom

06/13/2023

Step 1

Step 1: Write the chemical equation for the reaction of hydrazine in water: \[ N_2H_4(aq) + H_2O(l) \rightleftharpoons N_2H_5^+(aq) + OH^-(aq) \] Show more…

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For the reaction of hydrazine (N2H4) in water: N2H4(aq) + H2O(l) ⇌ N2H5+(aq) + OH-(aq) Kb is 3.0 x 10^-6. Calculate the concentrations of all species and the pH of a 2.9 M solution of hydrazine in water: [N2H4] [N2H5+] [OH-] [H+] pH =

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Transcript

00:01 Okay, for this problem we're asked to consider the chemical equation i'm about to write down, or that i am writing down.

00:06 That's hydrazine in solution.

00:10 We're going to add it with liquid water.

00:14 This will come to equilibrium with h2nnh3 plus and oh minus.

00:26 We're told that our kb for hydrazine is 3 .0 times 10 to the minus 6.

00:32 We're asked to calculate the concentration of all species at ph of 1 .3, and the ph, and ph at 1 .3 molar solution.

01:05 Okay, let's see if i can figure this one out.

01:11 We already have our chemical equation.

01:13 So let's see which species will contribute to the hydroxide ion concentration.

01:36 So what's going to contribute to this will be the nh2nnh2.

01:49 So my kb will equal oh minus times h2nnh3 plus over h2nnh.

02:06 And then we're going to figure out how our species change.

02:12 And i'm going to have my h2nnh will change as 1 .3 minus x.

02:22 And then my other two species will both be x.

02:25 So my kb, which was 3 .0 times 10 to the minus 6 will equal x squared over 1 .3 minus x.

02:47 We're going to assume that 1 .3 minus x is approximately equal to 1 .3.

02:52 So let me do second square root of 3 times 10 to the minus 6 times 1 .3...

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