00:01
In this question, it says that for the reaction of sulfur trioxide with water to produce sulfuric acid, how many grams of sulfuric acid can be produced from 250 grams of sulfur trioxide and 50 grams of water.
00:15
So let's solve it.
00:18
So let's write a balanced chemical equation for this reaction.
00:21
So we have our sulfur trioxide reacting with our water to produce our sulfuric so let's find for the mass of sulfuric acid produced by our water.
00:40
So our mass of water is given as 150 grams.
00:45
So let's find for the mass of our sulfuric acid produced by water.
00:53
So that would be equal to 150 grams of water times 1 mole of water divided by 18 grams per mole of water times 1 mole of sulfuric acid divided by 1 mole of water times the molar mass of sulfuric acid which is 98 grams per mole.
01:37
So that will give us an answer of 816 grams of sulfuric acid h2so4.
02:04
So let's find for the mass of our sulfuric acid produced from 250 grams of sulfur trioxide.
02:13
So mass of our sulfur trioxide so3 is given as 250 grams...