Question

For the reaction: H2(g) + I2(g) ? 2HI(g), K = 50.0. If the initial concentrations of H2, I2, and HI were 1.0 M, 0.5M and 0 M respectively, what will be the equilibrium concentrations of each of the three species? A. [H2] = 0.53 M; [I2] = 0.033 M; [HI] = 0.93 M B. [H2] = 0.066 M; [I2] = 0.53 M; [HI] = 0.53 M C. [H2] = 0.55 M; [I2] = 0.066M; [HI] = 0.63 M D. [H2] = 0.55 M; [I2] = 0.033 M; [HI] = 0.53 M E. [H2] = 0.27 M; [I2] = 0.066 M; [HI] = 0.53 M

          For the reaction: H2(g) + I2(g) ? 2HI(g), K = 50.0.
If the initial concentrations of H2, I2, and HI were 1.0 M, 0.5M and 0 M respectively, what will be the
equilibrium concentrations of each of the three species?
A.
[H2] = 0.53 M; [I2] = 0.033 M; [HI] = 0.93 M
B.
[H2] = 0.066 M; [I2] = 0.53 M; [HI] = 0.53 M
C.
[H2] = 0.55 M; [I2] = 0.066M; [HI] = 0.63 M
D.
[H2] = 0.55 M; [I2] = 0.033 M; [HI] = 0.53 M
E.
[H2] = 0.27 M; [I2] = 0.066 M; [HI] = 0.53 M

For the reaction: H2(g) + I2(g) ? 2HI(g), K = 50.0.
If the initial concentrations of H2, I2, and HI were 1.0 M, 0.5M and 0 M respectively, what will be the
equilibrium concentrations of each of the three species?
A.
[H2] = 0.53 M; [I2] = 0.033 M; [HI] = 0.93 M
B.
[H2] = 0.066 M; [I2] = 0.53 M; [HI] = 0.53 M
C.
[H2] = 0.55 M; [I2] = 0.066M; [HI] = 0.63 M
D.
[H2] = 0.55 M; [I2] = 0.033 M; [HI] = 0.53 M
E.
[H2] = 0.27 M; [I2] = 0.066 M; [HI] = 0.53 M

Added by Kristy M.

Chemistry: Structure and Properties

Nivaldo Tro 2nd Edition

Instant Answer

Solved by Expert John Incabo

07/16/2022

Step 1

Hg + I2 -> 2HI Show more…

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For the reaction:Hg+Ig-2HI(g.K=50.0 If the initial concentrations of H2l2,and HI were 1.0 M,0.5M and 0 M respectively,what will be the equilibrium concentrations of each of the three species A. [H]=0.53M[I2]=0.033M[HI]=0.93M B. [H2]=0.066M;[l2]=0.53M[HI]=0.53M [H2]=0.55M[I]=0.066M[HI]=0.63M [H2]=0.55M[I2]=0.033M[HI]=0.53M D E. [H]=0.27M[I]=0.066M[HI]=0.53M