Question

$\frac{1}{\frac{1}{x-3} + \frac{1}{x+4}}$ If $x > 0$ and $x \neq 3$, which of the following is equivalent to the expression above? A) $2x + 1$ B) $x^2 + x - 12$ C) $\frac{x^2 + x - 12}{2x + 1}$ D) $\frac{2x + 1}{x^2 + x - 12}$

          $\frac{1}{\frac{1}{x-3} + \frac{1}{x+4}}$
If $x > 0$ and $x \neq 3$, which of the following is
equivalent to the expression above?
A) $2x + 1$
B) $x^2 + x - 12$
C) $\frac{x^2 + x - 12}{2x + 1}$
D) $\frac{2x + 1}{x^2 + x - 12}$

(1)/((1)/(x-3) + (1)/(x+4))
If x > 0 and x ≠ 3, which of the following is
equivalent to the expression above?
A) 2x + 1
B) x^2 + x - 12
C) (x^2 + x - 12)/(2x + 1)
D) (2x + 1)/(x^2 + x - 12)

Added by Danielle W.

Calculus: Early Transcendentals

James Stewart 8th Edition

Instant Answer

Solved by Expert Lily An

05/16/2019

Step 1

$$\frac{1}{\frac{1}{x-3}+\frac{1}{x+4}}=\frac{1}{\frac{x+4+(x-3)}{(x-3)(x+4)}}$$ Show more…

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$$\frac{1}{\frac{1}{x-3}+\frac{1}{x+4}}$$ If $x>0$ and $x\neq3$, which of the following is equivalent to the expression above? A) $2x+1$ B) $x^2+x-12$ C) $\frac{x^2+x-12}{2x+1}$ D) $\frac{2x+1}{x^2+x-12}$