From the tree diagram find the following. (a) P(A ∩ E) (b) P(A) (c) P(A|E) A 0.2 0.3 E B 0.2 0.5 C 0.3 A 0.8 0.3 F B 0.4 C
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From the tree diagram, we can see that the probability of E occurring is 0.2, and given that E has occurred, the probability of A occurring is 0.2. Therefore, $P(A \cap E) = P(E) \times P(A|E) = 0.2 \times 0.2 = 0.04$. Show more…
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