For $0 \le x \le 1$, $f(x) = 2x - 2$.
For $1 \le x \le 2$, $f(x) = -x^2 + 2x$.
For $2 \le x \le 4$, $f(x) = 0$.
For $4 \le x \le 6$, $f(x) = x - 4$.
$g(x) = 3 + \int_2^x f(t) \, dt$
$g'(x) = f(x)$ by the Fundamental Theorem of Calculus.
$g''(x) = f'(x)$
a. Find
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