3. (A) What is the generation time of a bacterial population that increases from 2 to 128 in two hours? (B) What is the mean growth rate constant (k) in this situation? 4. For a particular bacterial culture, a student counted an average of 12 cells per square in a Petroff-Hausser counting chamber when the optical density at 600 nm is 0.05. If the optical density increases from 0.05 to 0.8 in eight hours, how many cells per mL should now be present in the culture? What is the mean growth rate constant (k) for this culture? 5. You performed spectrophotometric measurements to determine the grow rate of a bacterial cell culture and obtained the data shown below. Please plot the absorbance versus time on a logarithmic (base 10) scale to show the growth curve as a straight line. Find the slope of the line and calculate the generation time from the slope. You will first need to calculate the time elapsed (duration) for some of the data points shown in the table below. Time | Duration (min) | OD600 3:59 AM | 0 | 0.189 4:59 AM | 60 | 0.208 5:59 AM | 120 | 0.227 6:59 AM | 180 | 0.246 7:59 AM | | 0.262 8:59 AM | | 0.280 9:59 AM | | 0.302 10:59 AM | | 0.328 11:59 AM | | 0.357 12:59 PM | | 0.384
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First, we need to find the mean growth rate (k) for the bacterial culture. To do this, we can use the formula: k = (ln(N_t) - ln(N_0)) / t where N_t is the number of cells at time t, N_0 is the initial number of cells, and t is the time elapsed. Show more…
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