Question

Function avgEvens(array, size) { let sum = 0; let count = 0; for (let i = 0; i < size; i++) { if (array[i] % 2 === 0) { sum += array[i]; count++; } } return sum / count; } let numbers = [2, 3, 6, 8, 1, 5, 9, 12, 11, 22]; let size = 10; console.log("The average value of the even numbers is " + avgEvens(numbers, size));

Name: function avgevensarray size let sum 0 let count 0 for let i 0 i size i if arrayi 2 0 sum arrayi count return sum count let numbers 2 3 6 8 1 5 9 12 11 22 let size 10 consolelogthe average va 52032
Uploaded: 2023-11-20T02:33:15-08:00
Duration: 2 min 22 s
Channel: Akash M
Description: function avgevensarray size let sum 0 let count 0 for let i 0 i size i if arrayi 2 0 sum arrayi count return sum count let numbers 2 3 6 8 1 5 9 12 11 22 let size 10 consolelogthe average va 52032

          Function avgEvens(array, size) {
  let sum = 0;
  let count = 0;
  for (let i = 0; i < size; i++) {
    if (array[i] % 2 === 0) {
      sum += array[i];
      count++;
    }
  }
  return sum / count;
}

let numbers = [2, 3, 6, 8, 1, 5, 9, 12, 11, 22];
let size = 10;
console.log("The average value of the even numbers is " + avgEvens(numbers, size));

Added by Concepci-N C.

Computer Science and Information Technology

Trishna Knowledge Systems 2018 Edition

Instant Answer

Solved by Expert Akash M

11/20/2023

Step 1

Step 1: Initialize the sum variable to 0 and the count variable to 0. Show more…

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Function avgEvens(array, size) { let sum = 0; let count = 0; for (let i = 0; i < size; i++) { if (array[i] % 2 === 0) { sum += array[i]; count++; } } return sum / count; } let numbers = [2, 3, 6, 8, 1, 5, 9, 12, 11, 22]; let size = 10; console.log("The average value of the even numbers is " + avgEvens(numbers, size));