f(x) = \left(\frac{2\cos(3x)}{1 + e^{2x}}\right)^3 \newline f'(x) = 3\left(\frac{2\cos(3x)}{1 + e^{2x}}\right)^2 \cdot \frac{-6x\sin(3x)(1 + e^{2x}) - 2\cos(3x) \times 2e^{2x}}{(1 + e^{2x})^2} \newline = \frac{-12\cos(3x) \times [6(1 + e^{2x})\sin3x + 4e^{2x}\cos(3x)]}{(1 + e^{2x})^4}
Added by John R.
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