00:01
I actually think it might be easier to tell you the answer on the graph first, because you have x to the fourth plus one where x is greater than or equal to zero.
00:11
So if you understand your transformations, this graph is shifted up one, and we're only on the right side of the origin.
00:19
So as i'm looking at the graphs, in x to the fourth, it shoots up in the graph.
00:27
So it starts at 0 -1 and shoots up, and that's the graph of f.
00:33
And the only one that does that is the bottom right graph.
00:38
So i was going to write that in green.
00:41
The bottom right.
00:46
And its inverse would then be reflected over the line, as i mentioned, and it shoots to the right then.
00:52
And that's f inverse.
00:54
So let me go ahead and circle that.
00:56
Now the actual way to find the inverse, what i like to do is switch the x and the y coordinates around and then solve for y...