Question

(g) Heads up --- the bisection algorithm can't distinguish a vertical asymptote from a zero! What is the output of trying the bisection algorithm on f(x) = 1/x over the interval [-1, 1]? 0.6914 (a) Find the intersection point of the graphs y = 12/?x and y = e^x/12 for x > 0. Find an appropriate function and bracketing interval to apply the bisection method. What is the x value of the intersection point? 15.524 (e) Later in the course, we will compute the area between the graphs of two functions, such as f(x) = 2 - x^2 and g(x) = 3 - (2x)^2. To solve this problem, we must first determine when f(x) = g(x). In this case, for every intersection point with x > 0, by symmetry, there is another intersection point at -x. So if we assume that x > 0, find the x-value of the intersection point of the two graphs using fzero. (c) Let f(x) = 5x^4 - 6x^2 and g(x) = 22x^3 - 11x. What are the values of f at the zeros of g? -7,4

          (g) Heads up --- the bisection algorithm can't distinguish a vertical asymptote from a zero!
What is the output of trying the bisection algorithm on f(x) = 1/x over the interval [-1, 1]?
0.6914
(a) Find the intersection point of the graphs y = 12/?x and y = e^x/12 for x > 0. Find an appropriate function and bracketing interval to apply the bisection method. What is the x value of the intersection point?
15.524
(e) Later in the course, we will compute the area between the graphs of two functions, such as f(x) = 2 - x^2 and g(x) = 3 - (2x)^2. To solve this problem, we must first determine when f(x) = g(x). In this case, for every intersection point with x > 0, by symmetry, there is another intersection point at -x. So if we assume that x > 0, find the x-value of the intersection point of the two graphs using fzero.
(c) Let f(x) = 5x^4 - 6x^2 and g(x) = 22x^3 - 11x. What are the values of f at the zeros of g?
-7,4

(g) Heads up — the bisection algorithm can't distinguish a vertical asymptote from a zero!
What is the output of trying the bisection algorithm on f(x) = 1/x over the interval [-1, 1]?
0.6914
(a) Find the intersection point of the graphs y = 12/?x and y = e^x/12 for x > 0. Find an appropriate function and bracketing interval to apply the bisection method. What is the x value of the intersection point?
15.524
(e) Later in the course, we will compute the area between the graphs of two functions, such as f(x) = 2 - x^2 and g(x) = 3 - (2x)^2. To solve this problem, we must first determine when f(x) = g(x). In this case, for every intersection point with x > 0, by symmetry, there is another intersection point at -x. So if we assume that x > 0, find the x-value of the intersection point of the two graphs using fzero.
(c) Let f(x) = 5x^4 - 6x^2 and g(x) = 22x^3 - 11x. What are the values of f at the zeros of g?
-7,4

Added by Charles L.

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