00:10
All right, so genes a and b are on one chromosome, 20 map units apart, c and d are in another chromosome, 20 map units apart.
00:29
In the f2 pratchini, 4%, 6%, 8%, 16%, or 24%.
00:37
So to start off, since they're 20 map units apart, there would be strong probability to have independent assortment, and the genotype is big a, little a, big b, little b, big c, little c, little c, little d.
00:53
So the probability then of homozygous dominant, which would be a, a, b, c, c, d, d would be 1 out of 4...