00:01
Hello students, it is given that straight ear that is capital e is dominant over floppy ear that is small e, black fur is dominant that is capital b over brown fur that is small b, rabbit that is homozygous for straight ear and brown fur that is this is mated to a rabbit that is homozygous floppy ear and black fur and the genotype is this.
00:36
So by crossing this these are the gametes for each one of them by crossing them we got this 16 offsprings.
00:48
This is the f1 generation here you can see all the offspring genotype is capital e small e capital b small b that is the genotype is this and phenotype would will be straight ear and black fur.
01:05
Therefore the genotype and phenotype for f1 generation will be one raised to one ratio to one ratio to one ratio to one ratio.
01:14
So this will be the genotype and phenotype of f1 generation because here one of the gamete is same similar to the another and also the phenotype is same that is straight ear and black fur.
01:30
Now we'll take two of the offspring and will cross between them.
01:38
So let's say that we have crossed capital e small e capital b small b into capital e small e capital b small b.
01:48
So these four are the gametes and these are for male and these are for female.
01:55
So this is the f2 generation.
01:58
Next by crossing them we got this so here straight ear and black fur such individuals are nine in number that means they are exhibiting capital e and capital b these two dominant alleles...