Use the following atomic weights and quantities to calculate the overall % yield of (E)-stilbene. Remember that your yield must be based on the limiting reagent, volumes must be converted to grams, and grams to moles. Filling out most of the chart will help. Give only two significant digits in your answer. If after rounding the answer is a whole number, do not include a decimal point. C= 12, H = 1, O = 16, P = 31, Br = 80 formula formula weight density grams mL moles benzyltriphenylphosphonium bromide 43.234 benzaldehyde 1.044 9.788 % yield (E)-stilbene 5.032
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Calculate the moles of Benzyltriphenylphosphonium bromide: Moles = grams / formula weight Moles = 1.04 g / 430.23 g/mol Moles = 0.00242 mol Show more…
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Use the following atomic weights and quantities to calculate the overall % yield of (E)-stilbene. Remember that your yield must be based on the limiting reagent, volumes must be converted to grams, and grams to moles. Filling out most of the chart will help. Give only two significant digits in your answer. If after rounding the answer is a whole number, do not include a decimal point. C = 12, H = 1, O = 16, P = 31, Br = 80 benzyltriphenylphosphonium bromide + benzaldehyde -> (E)-stilbene formula formula weight density 1.044 grams 14.172 5.420 mL 27.794 moles % yield Answer:
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If 1.50 mL of benzaldehyde reacts with an excess of the Grignard reagent, calculate the theoretical yield (in grams) of the alcohol product. Show calculation with units for full credit: Density of benzaldehyde: 0.4 g/mL Mass = density x volume Mass = 0.4 g/mL x 1.50 mL Mass = 0.6 g 56 g Benzaldehyde = 106.12 g Benzaldehyde 136.19 g Pheny - propanol = 136.19 g/106.12 g Mass of I-phenyl-I-propanol = 56 g Actual yield/Theoretical yield x 100 (0.6 g/99 g) x 100 yield = 0.61% Theoretical yield = 99 g 6. If 1.12 grams of product are formed from 1.50 mL of benzaldehyde in this reaction, calculate the percent yield of the reaction.
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