Is 8a(a + b) a multiple of 4a?
Yes, because 8a(a + b) is a divisor of 4a.
Yes, because 8a(a + b) = 4a(2(a + b)) which is an integer because sums and products of integers are integers.
Yes, because 4 is a multiple of 8.
No, because 4 is not a divisor of 8.
No, because 8a(a + b) = 4a(2(a + b)) which may not be an integer because sums and products of integers are not always integers.