00:01
In this question we are asked to find the laplace transform of the function ft.
00:04
So let's start to solve this problem.
00:07
Laplace transform of any signal ft is given by integration 0 to infinity e to the power minus st ft d t.
00:20
From this we obtain laplace transform of ft is equal to fs equals to integration 0 to infinity a to the power minus st ft dt.
00:32
For the given function, for 0 to 3, ft is equal to 0.
00:41
Plus and for 3 to infinity, ft is equal to t minus 3 to the power negative stdt.
00:52
The value of this integration is equal to 0.
00:56
Fs is equal to integration 3 to infinity, t minus 3 to the power negative stdt.
01:06
Now by using integration by parts, the value of this integration comes equal to t minus 3 into integration of it to the power negative as t, that is, 0 to the power negative as t over negative as minus minus.
01:25
Minus derivative of t minus 3 and a derivative of t minus 3 is equal to 1 into integration of this...