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Hello students in this question we have been given an anion which is sulfur minus 2 which has atomic mass 38.
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We are asked to find out the number of protons, neutrons as well as the number of electrons.
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So we are going to use simple formulas as our concept.
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So let's see all of us know that a number of protons, protons, number of protons is always equals to the atomic number of the element.
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Atomic number is represented as z.
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The neutrons which here is represented as n is equals to the atomic number subtracted by the mass number and mass number is denoted as capital a.
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And the number of electrons we can simply find out by the position of the element in the periodic table by its electronic configurating.
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Sulfur is basically an element of 16th group and third period of the periodic table.
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The atomic number of sulfur is 16.
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So z equals to 16.
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There so therefore there will be 16 protons present in sulfur the mass number of sulfur we are already given which is equal to 38 so to find out the number of neutrons will subtract 16 which is the atomic number or the proton number of protons by the mass number which is equal to 38 so number of neutrons we get as 22 by the earlier discussion we already know that the element sulfur belongs to third period so it is going to have three cells which are one two and three and since it's belonged to the 16th group of the periodic table, then it's going to have 6 electron in its outermost shell...