Given a function $-2x^2 - 3x + 4$ Find the equation of the tangent line at $x = -7$ f(x) = f(-7) = = Write the equation in slope-intercept form $y = 25x + 80$ = Next, find the point on the curve
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$f(x) = -2x^2 - 3x + 4$ $f'(x) = -4x - 3$ Show more…
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