Given a mass, m=5 kg, attached to a spring with spring constant, k = 20 N/m: Assuming undamped system, setup the model and solve for the particular solution given initial conditions, y(0) = 15 y(?/4) = 10 y(t) = 15cos(2t) + 10sin(2t) y(t) = 15e^(2t) + 10e^(-2t) y(t) = 10cos(t) + 15sin(t) y(t) = 10e^(2t) + 15e^(-2t) None
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The equation of motion for a mass-spring system is given by: m * d^2y/dt^2 + k * y = 0 where m is the mass and k is the spring constant. In this case, m = 5 kg and k = 20 N/m, so the equation becomes: 5 * d^2y/dt^2 + 20 * y = 0 Show more…
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