Question

Given a normal distribution with ? = 52 and ? = 4, complete parts (a) through (d). a. What is the probability that X > 46? P(X > 46) = 0.9332 (Round to four decimal places as needed.) b. What is the probability that X < 44? P(X < 44) = 0.0228 (Round to four decimal places as needed.) c. For this distribution, 5% of the values are less than what X-value? X = (Round to the nearest integer as needed.)

          Given a normal distribution with ? = 52 and ? = 4, complete parts (a) through (d).

a. What is the probability that X > 46?
P(X > 46) = 0.9332 (Round to four decimal places as needed.)

b. What is the probability that X < 44?
P(X < 44) = 0.0228 (Round to four decimal places as needed.)

c. For this distribution, 5% of the values are less than what X-value?
X = (Round to the nearest integer as needed.)

Given a normal distribution with ? = 52 and ? = 4, complete parts (a) through (d).

a. What is the probability that X > 46?
P(X > 46) = 0.9332 (Round to four decimal places as needed.)

b. What is the probability that X < 44?
P(X < 44) = 0.0228 (Round to four decimal places as needed.)

c. For this distribution, 5% of the values are less than what X-value?
X = (Round to the nearest integer as needed.)

Added by Kenneth W.

Elementary Statistics a Step by Step Approach

Allan G. Bluman 9th Edition

Instant Answer

Solved by Expert Adi S

09/17/2023

Step 1

The z-score is calculated as: z = (X - μ) / σ where X is the value, μ is the mean, and σ is the standard deviation. Plugging in the given values: z = (46 - 52) / 4 = -6 / 4 = -1.5 Now, we look up the z-score in the cumulative standardized normal distribution Show more…

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Given a normal distribution with μ = 52 and σ = 4, complete parts (a) through (d): a. What is the probability that X > 46? P(X > 46) = 0.9332 (Round to four decimal places as needed.) b. What is the probability that X < 44? P(X < 44) = 0.0228 (Round to four decimal places as needed.) c. For this distribution, 5% of the values are less than what X-value? X = (Round to the nearest integer as needed.)