Given a random variable X with a binomial distribution with a mean = 7 and a variance of 2.1. a. What is the value of n? b. What is the value of p? c. What is the probability for P(3<X<8)?
Added by Derek R.
Step 1
We know that for a binomial distribution, the mean is given by $\mu = np$ and the variance is given by $\sigma^2 = np(1-p)$. We are given $\mu = 7$ and $\sigma^2 = 2.1$. b. We can use the relationship between the mean and variance to find the value of $p$. Show more…
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