Suppose X is a normal random variable with a mean of 10 and a standard deviation of 2. a) Find P(7 ≤ X ≤ 13). b) Find the value of c if P(X ≤ c) = 0.8729.
Added by Benjamin S.
Step 1
So, for x = 7: z1 = (7 - 10) / 2 = -1.5 And for x = 13: z2 = (13 - 10) / 2 = 1.5 Now, we can use a standard normal distribution table or calculator to find the probability of z being between -1.5 and 1.5. This probability is approximately 0.8664. Show more…
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