1. Given a vessel with V = 0.3 m³ filled with m = 1.5 kg of...

1. Given a vessel with V = 0.3 m³ filled with m = 1.5 kg of water at P = 600 kPa, find: a. the volume and mass of liquid b. the volume and mass of vapor 2. A vacuum gage connected to a chamber reads 6.5 psi at a location where the atmospheric pressure is 14.5 psi. Determine the absolute pressure in the chamber. 3. What are the properties of saturated liquid and saturated vapor for water at temperature 200°C? 4. 0.07 kg of water at 20°C in a container of 1.5 m³ volume. Find the phase description, pressure, and quality (if appropriate)? Use the Property Tables and Charts (SI UNITS). 5. 0.03 kg of water at 10°C in a container of 0.6 m³ volume. Find the phase description, pressure, and quality (if appropriate)? Use the Property Tables and Charts (SI UNITS).

Transcript

00:01 Hello students.

00:01 So our question is given a vessel with vs equals to 0 .3 meter cube filled with a mass 1 .5 kg of water at pressure 600 kilo pascal.

00:11 Find the volume and mass of liquid and the volume and mass of vapor.

00:15 So let's see the given quantity is first.

00:18 Given first the volume that is 0 .3 meter cube.

00:31 Second the mass that is 1 .5 kg and third is pressure.

00:41 That is 600kcal so we have to find out the volume and mass of liquid and vapor so let's say it so from the table at 600 kioscal pressure value of vf and vg not given by approximation value of vf and vg we can take this the approximation value vf is 0 .0 .0110 meter q per kilogram okay and the value of vg that is volume of gase is we can tag at 0 .310 meter cube per kilogram okay so vf plus vz is equal to the complete volume v okay and this is the equation one we can say n ml plus mv is equal to complete m this is equation 2 okay so from here we can write down the value of vf and vg.

01:45 How is this? vf is ml multiplied by vf and vg is v v multiplied by vg.

02:02 So if you will put these both values in equation 1 then ml vf plus mvvg is equals to v.

02:17 Okay so from here so as we know the value of vf and vg is equal to v.

02:22 So from here ml the value of vf is 0 .001 plus mb multiply by the value of vj is 0 .31080 is equal to the value of v is given 0 .3 .3.

02:41 Okay.

02:42 So from here ml plus mv is equal to 1 .5.

02:51 You can say it equation number 3.

02:53 This is equation from so by equation 1 .1.

02:58 So, equation 3 and 4, the value of ml is 0 .536 kg and value of mv is 0 .963 kg.

03:14 So from here we can easily solve part a and b that says that volume of liquid that is 0 .589 multiply by 10 to the power minus 3 meter cube and the mass of liquid...

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