00:01
This question says that given s t is equal to 5 t square plus 5 t where s t is in fit and t is in seconds.
00:09
Find each of the following.
00:11
Number a, vt, number b, a, t, number c, the velocity and acceleration when t equals to 4 second.
00:19
So let's start to solve these problems.
00:22
Here as t is the displacement and we know derivative of displacement is equal to velocity.
00:32
That means velocity vt is equal to d over dt of st.
00:39
D over dt of st is equal to 5t square plus 5t.
00:47
5 d over dt of t square plus 5 d over dt of t.
00:56
5 derivative of t square 2t plus 5 derivative of t with respect to t is equal to 1.
01:02
From this we obtained vt that is velocity is equal to 10 t plus 5...