Question

Given that $\lim_{x\to 0} \frac{\exp(x)-1}{x} = 1$, find $\lim_{x\to 0} \frac{\exp(4x)-1}{x}$. Enter I for $\infty$, -I for $-\infty$, and DNE if the limit does not exist. Answer:

          Given that $\lim_{x\to 0} \frac{\exp(x)-1}{x} = 1$, find $\lim_{x\to 0} \frac{\exp(4x)-1}{x}$.

Enter I for $\infty$, -I for $-\infty$, and DNE if the limit does not exist.
Answer:

Given that limx→ 0((x)-1)/(x) = 1, find limx→ 0((4x)-1)/(x).

Enter I for ∞, -I for -∞, and DNE if the limit does not exist.
Answer:

Added by Sarah M.

Calculus: Early Transcendentals

James Stewart 8th Edition

Instant Answer

Solved by Expert Vincenzo Zaccaro

01/15/2023

Step 1

Step 1: Use the limit property that if lim(x->a) f(x) = L and lim(x->a) g(x) = M, then lim(x->a) [f(x) + g(x)] = L + M. Show more…

Show all steps

Thanks for your feedback!

Given that lim_(x->0)(exp(x)-1)/(x)=1, find lim_(x->0)(exp(4x)-1)/(x). Enter I for infty ,- I for -infty , and DNE if the limit does not exist. Answer: Given that limr-0 exp(4x)-1 Enter I for oo, -I for --oo, and DNE if the limit does not exist Answer: