Given the accompanying diagram and the following information, briefly describe the transport mechanism (i.e., simple, passive-mediated, primary active, or secondary active transport, or any combinations of the above) for the net movement of glucose from the intestinal lumen through epithelial cells into the blood stream. Apical surface Basal surface Intestinal lumen Blood Microvilli Epithelial cell 2 K+ 3 Na+ 2 Na+ Na+K+ ATPase Glucose Glucose a) [glucose] in intestinal lumen = 50 ?M b) [glucose] in epithelial cells = 25 mM c) [glucose] in blood = 5 mM d) [Na+] in intestinal lumen = 145 mM e) [Na+] in epithelial cells = 12 mM f) [Na+] in blood stream = 145 mM g) [K+] in epithelial cells = 140 mM h) [K+] in blood stream = 4 mM
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Glucose moves from the intestinal lumen into the epithelial cells. Since the concentration of glucose is higher in the intestinal lumen (50 µM) than in the epithelial cells (25 mM), this movement is likely facilitated by a co-transporter that uses the Na+ gradient Show more…
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