Given the conic section $r = frac{6}{4 + 8sin( heta)}$, find the x and y intercept(s) and the focus(foci). Intercept(s): (0,2),(0,0) Focus(foci): (0,0) Give answers as a list of one or more ordered pairs, separated by commas.
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The equation given is in polar form, so we can convert it to Cartesian form using the identity r^2 = x^2 + y^2: (x^2 + y^2) = 4 + 8sin(θ) Simplifying this equation, we get: x^2 + y^2 = 4 + 8y This is the equation of a circle with center at (0, 4) and radius 2. Show more…
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