00:01
Hello students, we are given with the values that is x f of x which are 1 .6, 2, 2 .5, 3 .2 and f of x are 2, 8, 14, 15 and we have to use newton's interpolating polynomial to find the value of x at 2 .8 from the order 1, 2, 3.
00:36
So, here first let us write down the values of f of xi, xi plus 1 that will be 3, 2 and here it will be 0 .33 and next f of xi, xi plus 1, xi plus 2 will become minus 0 .5 minus 1 same way f of xi, xi plus 1, xi plus 2, xi plus 3.
01:22
So, that will be equal to 0 .25.
01:28
Now, first let us find the value of p1 of x at 2 .8.
01:41
So, that is we are going to find the order for 1.
01:46
So, the formula will be of.
01:52
So, first let us write down the formula p1 of x is equal to f of x2 plus f of x2 comma x3, x minus x2.
02:09
Now, using the above formula we can find p1 of 0, 2 .8 that will be equal to 14 plus 2 into 2 .8 minus 2 .5 which is equal to 14 plus 2 into 0 .3...