Question

Given the equation below, find $\frac{dy}{dx}$. $-27x^9 + 5x^{18}y + y^4 = -21$ $\frac{dy}{dx} = $ Now, find the equation of the tangent line to the curve at $(1, 1)$. Write your answer in $mx + b$ format y =

          Given the equation below, find $\frac{dy}{dx}$.
$-27x^9 + 5x^{18}y + y^4 = -21$
$\frac{dy}{dx} = $
Now, find the equation of the tangent line to the curve at $(1, 1)$. Write your answer in $mx + b$ format
y =

Given the equation below, find (dy)/(dx).
-27x^9 + 5x^18y + y^4 = -21
(dy)/(dx) =
Now, find the equation of the tangent line to the curve at (1, 1). Write your answer in mx + b format
y =

Added by Kimberly D.

Calculus: Early Transcendentals

James Stewart 8th Edition

Instant Answer

Solved by Expert Supreeta N

06/27/2023

Step 1

Taking the derivative of each term with respect to x: -27(9x^8) + 5(18x^17)(dy/dx) + 4y^3(dy/dx) = 0 -243x^8 + 90x^17(dy/dx) + 4y^3(dy/dx) = 0 Solving for (dy/dx): 90x^17(dy/dx) + 4y^3(dy/dx) = 243x^8 (dy/dx)(90x^17 + 4y^3) = 243x^8 (dy/dx) = 243x^8 / (90x^17 + Show more…

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Given the equation below, find (dy)/(dx). -27x^(9)+5x^(18)y+y^(4)=-21 du Now, find the equation of the tangent line to the curve at (1,1). Write your answer in mx+b format y= Given the equation below,find dy dx 27x9+5x18y+y4=-21 dy dx Now, find the equation of the tangent line to the curve at (1,1).Write your answer in m+ b format Question Help:Video MM