Question

Given the following boiling points, determine the molality of each water solution. $$ \begin{array}{l}{\text { a. } 100.25^{\circ} \mathrm{C}} \\ {\text { b. } 101.53^{\circ} \mathrm{C}} \\ {\text { c. } 102.805^{\circ} \mathrm{C}}\end{array} $$

          Given the following boiling points, determine the molality of each water solution.
$$
\begin{array}{l}{\text { a. } 100.25^{\circ} \mathrm{C}} \\ {\text { b. } 101.53^{\circ} \mathrm{C}} \\ {\text { c. } 102.805^{\circ} \mathrm{C}}\end{array}
$$

Added by Jose Angel V.

Chemistry: Structure and Properties

Nivaldo Tro 2nd Edition

Instant Answer

Solved by Expert Suman K

06/27/2022

Step 1

512 °C/m), and $m$ is the molality of the solution. We can rearrange the equation to solve for $m$: $$m = \frac{\Delta T}{K_b}$$ Now let's calculate the molality for each boiling point: a. $\Delta T = 100.25 - 100 = 0.25 °C$ $$m = \frac{0.25}{0.512} = 0.488 \, Show more…

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Given the following boiling points, determine the molality of each water solution. $$ \begin{array}{l}{\text { a. } 100.25^{\circ} \mathrm{C}} \\ {\text { b. } 101.53^{\circ} \mathrm{C}} \\ {\text { c. } 102.805^{\circ} \mathrm{C}}\end{array} $$