00:01
I let's start the solution in this question we have given f of x is 1 upon 3 x cube minus 8 x squared plus kx then find the value of k for which k is a 1 1 function so first we differentiate f of x we get 3 x square upon 3 minus 16 x plus so now we get x square minus 16 x plus k that is f -des -x put f -des -x is 0.
00:37
So we get x square minus 16x plus k is 0.
00:41
So if we put k equal to 64.
00:52
So here we get x square minus 16x plus 64 equal to 0 and then we get factorization x minus 8 into x minus 8 is 0.
01:02
So that means here we get x is 8.
01:06
Now check whether it is satisfied or not.
01:12
So put this one is equation 1.
01:16
In 1, x square minus 16 x plus k.
01:22
So x square 8 square minus 16 into 8 plus 64 that gives this one is minus 64 plus 64 that is 0.
01:35
So, k equal for k equal to 64 function is 1 -1.
01:47
So now if we take if k is greater than 64, then here we get let k is 65...