Question

Given the following initial value problem (IVP): x' = [egin{array}{cc} -6 & 3 \ -3 & -6 end{array}] x + [egin{array}{c} 0 \ e^{-6t} end{array}], x(0) = [egin{array}{c} 0 \ 0 end{array}] The solution to the given IVP has the form: x(t) = Ce^{alpha t} [egin{array}{c} gamma - cos(eta t) \ sin(eta t) end{array}]. Fill in the blanks with the correct numbers: (Note: To enter a fraction frac{a}{b}, you can enter a/b. For example, frac{1}{6} can be entered as 1/6). C = ? = ? = ? =

          Given the following initial value problem (IVP):
x' = [egin{array}{cc} -6 & 3 \ -3 & -6 end{array}] x + [egin{array}{c} 0 \ e^{-6t} end{array}], x(0) = [egin{array}{c} 0 \ 0 end{array}]
The solution to the given IVP has the form:
x(t) = Ce^{alpha t} [egin{array}{c} gamma - cos(eta t) \ sin(eta t) end{array}].
Fill in the blanks with the correct numbers:
(Note: To enter a fraction frac{a}{b}, you can enter a/b. For example, frac{1}{6} can be entered as 1/6).
C =
? =
? =
? =

$Given the following initial value problem (IVP): x' = [eginarraycc -6 3 -3 -6 endarray] x + [eginarrayc 0 e^-6t endarray], x(0) = [eginarrayc 0 0 endarray] The solution to the given IVP has the form: x(t) = Ce^alpha t [eginarrayc gamma - cos(eta t) sin(eta t) endarray]. Fill in the blanks with the correct numbers: (Note: To enter a fraction fracab, you can enter a/b. For example, frac16 can be entered as 1/6). C = ? = ? = ? =$

Added by Daniel D.

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