00:01
So don't be fooled by this problem.
00:03
We're looking at f of x is equal to x plus 1 over x.
00:08
Because the main value theorem does apply from 1 to 5.
00:15
The issue with the mean value theorem is that it needs to be differentiable and continuous on this interval.
00:26
And so yes, the only issue that we have is that x equals.
00:31
Zero and that's not part of our intervals.
00:34
So we're good to do this.
00:37
The first thing you want to do is figure out what f of 1 is.
00:40
And i think that's pretty easy to do because it's 1 plus 1 over 1.
00:44
So it's going to be 2.
00:46
Whereas f of 5 is not as easy.
00:49
It's 5 plus 1 over 5, which instead of writing us the mixed number, i would rather write this as 26 5th.
00:59
You know, 5 times 5 is 25 plus 1...