given the function f(x)=x^(2)+8 and the point P=(-4,24) determine the equation of a tangent line at f(x) at P is y =
Added by Anna J.
Step 1
To do this, substitute x = -4 into the function: f(-4) = (-4)^2 + 8 = 16 + 8 = 24. Since f(-4) = 24, the point P is indeed on the curve. Show more…
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