00:01
Hello, so we have to solve this question by the laplace formula.
00:07
Writing the differential equation y double dash minus 4y is equal to 4 into delta of t minus 3 given y of 0 as minus 1 and y dash of 0 as 2.
00:24
Now taking laplace of y double dash minus 4y is equal to laplace of 4 into delta of t minus 3.
00:38
Laplace of y double dash minus 4 into laplace of y will be 4 into laplace of delta of t minus 3.
00:49
Y of 0 is minus 1, y dash of 0 is 2.
00:58
So we can here say that now laplace of delta of t minus 3 is e raised to minus 3 is laplace of y of 0 is laplace of minus 1.
01:20
Laplace of y dash of 0 is laplace of 2.
01:31
So y of s will be minus 1 by s.
01:35
S y of s minus y of 0 is it is equal to 2.
01:45
Further we can say that s y of s plus 1 is 2.
01:52
S y of s will be 1 by s.
01:57
So now we will say that s square y of s minus 4 y of s is equal to 4...