Giving the position function X(t) = 3t2 + 2t, what is the acceleration when t = 3?
Added by Dana M.
Step 1
The position function is given as X(t) = 3t² + 2t. The derivative of X(t) is: V(t) = dX/dt = d(3t² + 2t)/dt = 6t + 2. Show more…
Show all steps
Close
Your feedback will help us improve your experience
Madhur L and 91 other Calculus 1 / AB educators are ready to help you.
Ask a new question
Labs
Want to see this concept in action?
Explore this concept interactively to see how it behaves as you change inputs.
Key Concepts
Recommended Videos
the position of a particle moving on a straight track is given by {x=(6+9t+3t^2)m} what is acceleration 'a' at t=2 second?
Madhur L.
A particle's velocity function is given by V = 3t^3 + 5t^2 - 6, with V in meters/second and t in seconds. Find the acceleration at t = 3s.
A particle's velocity function is given by V = 3t^3 + 5t^2 - 6 with V in meters/second and t in seconds. Find the acceleration at t = 3s.
Pritesh R.
Recommended Textbooks
Calculus: Early Transcendentals
Thomas Calculus
Transcript
18,000,000+
Students on Numerade
Trusted by students at 8,000+ universities
Watch the video solution with this free unlock.
EMAIL
PASSWORD