00:01
Hello everyone, in this question it is given that f is twice differentiable function defined on minus 1 .2 less than x less than 3 .1 and they have given f of 1 as 2.
00:19
So the derivative of the graph f is also shown in the graph and they have given the function g of x as e to the power f of x.
00:28
So the question is to find equation of the line tangent to the graph of g at x equal to 1.
00:48
So the solution for this is first at x is equal to 1 we have to find g of 1.
00:55
So g of x they have given e to the power f of x.
01:00
So we will be having e to the power f of 1.
01:04
F of 1 is 2 from the given question.
01:06
So we have g of 1 as e square.
01:11
Next we have to find g dash of 1.
01:14
So g dash of 1 will be is nothing but g dash of x.
01:19
First g dash of x is e to the power f of x f dash of x.
01:27
So e dash of 1 will be e of f of 1 f dash of 1...