Question

Find and graph y[n], where y[n] = x[n] * h[n]. Operation * denotes convolution operation, where \\ i = \sqrt{-1}. \\ x[n] = i (\delta[n - 1] - \delta[n - 2] + \delta[n - 3] - \delta[n - 5]) \\ h[n] = i (\delta[n] + 2\delta[n - 1] + 3\delta[n - 2] - 4\delta[n - 4])

          Find and graph y[n], where y[n] = x[n] * h[n]. Operation * denotes convolution operation, where \\
i = \sqrt{-1}. \\
x[n] = i (\delta[n - 1] - \delta[n - 2] + \delta[n - 3] - \delta[n - 5]) \\
h[n] = i (\delta[n] + 2\delta[n - 1] + 3\delta[n - 2] - 4\delta[n - 4])

Find and graph y[n], where y[n] = x[n] * h[n]. Operation * denotes convolution operation, where

i = √(-1).

x[n] = i (δ[n - 1] - δ[n - 2] + δ[n - 3] - δ[n - 5])

h[n] = i (δ[n] + 2δ[n - 1] + 3δ[n - 2] - 4δ[n - 4])

Added by Veronica M.

University Physics with Modern Physics

Hugh D. Young 14th Edition

Instant Answer

Solved by Expert Akash M

09/04/2023

Step 1

Given: x[n] = i(8[n-1]-8[n-2]+8[n-3]-0[n-5]) h[n] = i8[n]+28[n1]+38[n-2]-48[n-4] We can simplify x[n] and h[n] as follows: x[n] = i(8[n-1]-8[n-2]+8[n-3]-0[n-5]) = i(8n-8-8n+16+8n-24) = i(-16) h[n] = i8[n]+28[n1]+38[n-2]-48[n-4] = Show more…

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graph should be handwritten drawn ... I'll downvote if u don't post handwritten graph Find and graph y[n], where y[n] = [n] * h[n]. Operation * denotes convolution operation, where i=v-1. x[n]=i(8[n-1]-8[n-2]+8[n-3]-0[n-5]) h[n]=i8[n]+28[n1]+38[n-2]-48[n-4])