00:01
For this, problem we are to graph the integrand of the integral from negative 1 to 3 of x over 2 plus 3dx, and you will use that graph to evaluate this integral.
00:11
Now, the integrand is the function x over 2 plus 3, and we want to graph it over the interval negative 1 to 3.
00:25
And since this is just a line, then we can simply get the points, of this function, when x is negative 1 and when x is 3.
00:36
So if x is negative 1, f of negative 1 is negative 1 over 2 plus 3, that's equal to 5 over 2.
00:49
And if x is 3, we have f of 3 equal to 3 halves plus 3, that's equal to 9 o 'clock 3.
01:00
Over 2.
01:02
So we plot the points negative 1, 5 over 2, and 3, 9 over 2, and then we connect them to form the line.
01:13
This should be our graph...