Question

Guess the value of the limit (if it exists) by evaluating the function at the given numbers. (It is suggested that you report answers accurate to at least six decimal places.) \text{Let } f(x) = \frac{\cos(3x) - \cos(6x)}{x^2} \text{We want to find the limit } \lim_{x \to 0} \frac{\cos(3x) - \cos(6x)}{x^2} \text{Start by calculating the values of the function for the inputs listed in this table.} \begin{array}{|c|c|} \hline x & f(x) \\ \hline 0.2 & \\\hline 0.1 & \\\hline 0.05 & \\\hline 0.01 & \\\hline 0.001 & \\\hline 0.0001 & \\\hline 0.00001 & \\\hline \end{array} \text{Based on the values in this table, it appears } \lim_{x \to 0} \frac{\cos(3x) - \cos(6x)}{x^2} =

          Guess the value of the limit (if it exists) by evaluating the function at the given numbers. (It is suggested that you report answers accurate to at least six decimal places.)
\text{Let } f(x) = \frac{\cos(3x) - \cos(6x)}{x^2}
\text{We want to find the limit } \lim_{x \to 0} \frac{\cos(3x) - \cos(6x)}{x^2}
\text{Start by calculating the values of the function for the inputs listed in this table.}
\begin{array}{|c|c|}
\hline x & f(x) \\
\hline 0.2 &  \\\hline 0.1 &  \\\hline 0.05 &  \\\hline 0.01 &  \\\hline 0.001 &  \\\hline 0.0001 &  \\\hline 0.00001 &  \\\hline
\end{array}
\text{Based on the values in this table, it appears } \lim_{x \to 0} \frac{\cos(3x) - \cos(6x)}{x^2} =

Guess the value of the limit (if it exists) by evaluating the function at the given numbers. (It is suggested that you report answers accurate to at least six decimal places.)
Let f(x) = (cos(3x) - cos(6x))/(x^2)
We want to find the limit limx →0 (cos(3x) - cos(6x))/(x^2)
Start by calculating the values of the function for the inputs listed in this table.

x f(x)
0.2
0.1
0.05
0.01
0.001
0.0001
0.00001

Based on the values in this table, it appears limx →0 (cos(3x) - cos(6x))/(x^2) =

Added by Virginia S.

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