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4. A body with mass 250 g is attached to the end of a spring that has a spring constant 5 N/m that is hanging from the ceiling. At time $t = 0$, the mass is pulled down from its static equilibrium position by 1 m then released without any initial velocity. Find the equation of motion. Only set it up Only set up the problem. Do not solve.

          4. A body with mass 250 g is attached to the end of a spring that has a spring constant 5 N/m that is hanging from the ceiling. At time $t = 0$, the mass is pulled down from its static equilibrium position by 1 m then released without any initial velocity. Find the equation of motion. Only set it up Only set up the problem. Do not solve.
        
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4. A body with mass 250 g is attached to the end of a spring that has a spring constant 5 N/m that is hanging from the ceiling. At time t = 0, the mass is pulled down from its static equilibrium position by 1 m then released without any initial velocity. Find the equation of motion. Only set it up Only set up the problem. Do not solve.

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Calculus: Early Transcendentals
Calculus: Early Transcendentals
James Stewart 8th Edition
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Hanging from the ceiling. At time t=0, the mass is pulled down from its static equilibrium position. Only set up the problem. Do not solve.
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Transcript

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00:01 So in this question, the equilibrium point after stretching is given as force of gravity should be equal to k times delta y.
00:20 So we can write this as mz and this should be equal to k times h and the omega that is angular frequency is given by k divided by m where k is the stiffness coefficient where k is the stiffness constant of the spring and m is the mass.
00:37 And this is equal to we can write here k divided by m and this will be equal to z divided by h.
00:46 So we can write this as square root of z divided by h.
00:50 So this omega will be equal to square root of g is 9 .8 and h is given as 0 .5.
00:58 So this will be equal to 4 .43 second inverse...
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