00:01
Hello students, here in this question we have to find out delta h and delta u value.
00:05
So here first of all we are considering the case of first reversible process.
00:20
So here at constant pressure we can say the q will be equal to n integral of t1 to t2 cp dp.
00:36
So using the particle gas equation we can find out the volume 2 that is volume 1 divided by volume 1 into p1 divided by p2.
00:49
So this value we will get is 0 .004958 meter cube.
00:56
So here in the first process what we have to first find is the temperature at the end process that will be equal to t1 into v2 divided by v1.
01:05
So that will be here is equal to if t1 value is 298 .15 and the v2 value we found it as 0 .004958 divided by the p2 value that is 0 .0247 iron and we will get the t dash value as 59 .63 kelvin.
01:26
So here in this question first of all we have to find out the q value that will be equal to delta h equal to cp delta t that is equal to 29 .10 into 59 .63 minus 298 .15.
01:42
So that is will be equal to 6940 .93 joule where the delta u value will be equal to delta h minus p delta v value that is equal to minus 6940 .93 minus 1 into 10 raised to 5 into 0 .004958 minus of 0 .0247 iron that is equal to minus 4958 joule...